Multiplication of two numbers where first digits are same and second digits sum is 10
>> Saturday, August 17, 2013
Today we will learn how to multiply two numbers having first digits same and sum of second digits is 10 using vedic methods.
Let's understand it through examples.
Example 1: 47*43
Here first digits are same, i.e. 4. Sum of second digits is 7 + 3 = 10.
This is exactly the conditions we are talking.
How to find the multiplication result:
Multiply 4 by 4+1, i.e. 4*(4+1)=20
Multiply last two digits, i.e. 7*3 = 21
Now the result is, 47 * 43 = [4*(4+1)][7*3]=[20][21]=2021
Example 2: 52*58
52*58 = [5*(5+1)][2*8] = [30][16]=3016
Example 3: 84*86
84*86 = [8*(8+1)][4*6] = [72][24]=7224
Example 4: 75*75
75*75 = [7*(7+1)][5*5] = [56][25]=5625
Example 5: 69*61
69*61 = [6*(6+1)][9*1] = [42][09]=4209
Note that in this example, we had to add 0 to make second part a two digit number.
